18x^2-49=0

Solution for 18x^2-49=0 equation:

18x^2-49=0

a = 18; b = 0; c = -49;
Δ = b2-4ac
Δ = 02-4·18·(-49)
Δ = 3528
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3528}=\sqrt{1764*2}=\sqrt{1764}*\sqrt{2}=42\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-42\sqrt{2}}{2*18}=\frac{0-42\sqrt{2}}{36}
=-\frac{42\sqrt{2}}{36}
=-\frac{7\sqrt{2}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+42\sqrt{2}}{2*18}=\frac{0+42\sqrt{2}}{36}
=\frac{42\sqrt{2}}{36}
=\frac{7\sqrt{2}}{6}
$